NutFullHouseOrFourOfAKind

[__Trueno__]

hi,

I would like to know a bit more asbout the way the bot computes the NutFullHouseOrFourOfAKind variable.

Are only board paired cards considerd, or the bot considers all of them?

I mean, if a pair is present in the board and also an Ace, the first nut is the Four-of-a-Kind of the paired card but the second will always be the full-house with Aces (two hole aces). Is this correct?

[Egor]

Board = 477A

NutFullHouseOrFourOfAKind values are as follows:

1 = 77
2 =  AA
3 = 7A
4 = 74
5 = 44

I don't recommend using the < > symbols with this variable

[irobot]

Why are option 3, 4 and 5 mentioned? They are not NutFullHouse or FourOfAKind values are they? Or is the NuttFullHouseOrFourOfAKind value also true when bot has second best fullhouse etc.?

[jbj81]

Why are option 3, 4 and 5 mentioned? They are not NutFullHouse or FourOfAKind values are they? Or is the NuttFullHouseOrFourOfAKind value also true when bot has second best fullhouse etc.?

I think the variable name is referring to Quads/FullHouse rank, not the "nut" value of a hand. And the rank when including all possible quads and full houses.

[Egor]

Right. Perhaps the variable is not well-named. It's simply a ranking system for the best possible hands when a pair in on board.

[irobot]

So the NutFullHouseOrFourOfAKind isn't used as when have NutFullHouseOrFourOfAKind .... but as when NutFullHouseOrFourOfAKind = 1 or when NutFullHouseOrFourOfAKind = 2 ....  ?

[sngbot]

[Egor]

It is not a boolean variable (true or false)

It is a numeric-valued variable, so must be used with < = >

[irobot]

It is not a boolean variable (true or false)

It is a numeric-valued variable, so must be used with < = >

Now I understand; thanks!

[__Trueno__]

Board = 477A

NutFullHouseOrFourOfAKind values are as follows:

1 = 77
2 =  AA
3 = 7A
4 = 74
5 = 44

I don't recommend using the < > symbols with this variable

How about when TripsOnBoard? Is this correct?
Board: 4777K

1 = 7
2 = KK
3 = AA
4 = K
5 = QQ
6 = JJ
...
...
12 = 55
13 = 4
14 = 33
15 = 22

[Egor]

Yes